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now thats some math i can get done,

LA_Boxers wrote:

That's numberwang!

take
n as any integer variable
gT as the total number of groups
g2 as the number of groups of size 2
g3 as the number of groups of size 3

we know

gT = g2 + g3

to find the best total number of groups:

gT = 4*round(n/10)

due to the way changing a group from 2 to 3 allows us to count up in increments of 1 it is quite simple

g2 = 3gT - n
g3 = -2gT + n

you will see that some values of n are not solvable, such as 13, 14, 15 and of course any n < 8

Oooooo...that looks like just what I was after. Thanks

Type "spy" in at the MATLAB terminal. It will blow your mind

is that the one that draws the picture of spy vs spy as a graph?

i went through all the easter eggs when i was bored last year

aww shame i missed this, that's what i get for having a life i guess but i've still managed to figure something out for you wubbz

Xi = {2,3} so as a function you could say X(0) = 2, X(1) = 3 and f(x) = X(x) where x is either 0 or 1.

so now you have S total things but the number of groups needs to be divisible by four yes?

put N to be the number of groups: then N % 4 = 0 and the % is the modulus which gives the remainder of N/4

umm you also got S = Sum of X_i from i = 1 to N.

there are alot of possible combos for the actual groups, there's no one formula to get all the x_i's as you've seen in this thread.

my suggestion to you though would be to look at different combos of different configurations of groups and forget about the ones that don't have N be a multiple of 4.

i'll break it down for you since i'm such a darl

N = number of groups
S = total number of things
X_i = number of objects in group i where i is a whole number from 1 to N and
S = Sum X_i i = 1 to N
N % 4 = 0
X(a) = 2 if a = 0 or X(a) = 3 if a = 1 and a can only equal 0 or 1

.

goddamn work computer always double posts.

LACE wrote:aww shame i missed this, that's what i get for having a life i guess but i've still managed to figure something out for you wubbz

Xi = {2,3} so as a function you could say X(0) = 2, X(1) = 3 and f(x) = X(x) where x is either 0 or 1.

so now you have S total things but the number of groups needs to be divisible by four yes?

put N to be the number of groups: then N % 4 = 0 and the % is the modulus which gives the remainder of N/4

umm you also got S = Sum of X_i from i = 1 to N.

there are alot of possible combos for the actual groups, there's no one formula to get all the x_i's as you've seen in this thread.

my suggestion to you though would be to look at different combos of different configurations of groups and forget about the ones that don't have N be a multiple of 4.

i'll break it down for you since i'm such a darl

N = number of groups
S = total number of things
X_i = number of objects in group i where i is a whole number from 1 to N and
S = Sum X_i i = 1 to N
N % 4 = 0
X(a) = 2 if a = 0 or X(a) = 3 if a = 1 and a can only equal 0 or 1

Half base x height

I feel retarded looking at your guys posts.

1+1 is 2.

^ way to be a stereotype

So is the aim to determine the minimum number of groups needed?
If so then I think I have a solution and could upload a dodgy .exe program today if you want.

Select Windows or Linux

LACE wrote:aww shame i missed this, that's what i get for having a life i guess but i've still managed to figure something out for you wubbz

Xi = {2,3} so as a function you could say X(0) = 2, X(1) = 3 and f(x) = X(x) where x is either 0 or 1.

so now you have S total things but the number of groups needs to be divisible by four yes?

put N to be the number of groups: then N % 4 = 0 and the % is the modulus which gives the remainder of N/4

umm you also got S = Sum of X_i from i = 1 to N.

there are alot of possible combos for the actual groups, there's no one formula to get all the x_i's as you've seen in this thread.

my suggestion to you though would be to look at different combos of different configurations of groups and forget about the ones that don't have N be a multiple of 4.

i'll break it down for you since i'm such a darl

N = number of groups
S = total number of things
X_i = number of objects in group i where i is a whole number from 1 to N and
S = Sum X_i i = 1 to N
N % 4 = 0
X(a) = 2 if a = 0 or X(a) = 3 if a = 1 and a can only equal 0 or 1

wub wrote:

fucking hell you guys are smart

Reverb wrote:fucking hell you guys are smart

Thank you

Reverb wrote:fucking hell you guys are smart

Do some phyiscs, you'll soon realize a page long equation is not always right.