Dubstepforum.com

Electric_Head wrote:

Reverb wrote:fucking hell you guys are smart

Do some phyiscs, you'll soon realize a page long equation is not always right.

fractal wrote:^ that is the beauty of Wolfram Alpha

you can always check your answer

fractal wrote:

LACE wrote:aww shame i missed this, that's what i get for having a life i guess but i've still managed to figure something out for you wubbz

Xi = {2,3} so as a function you could say X(0) = 2, X(1) = 3 and f(x) = X(x) where x is either 0 or 1.

so now you have S total things but the number of groups needs to be divisible by four yes?

put N to be the number of groups: then N % 4 = 0 and the % is the modulus which gives the remainder of N/4

umm you also got S = Sum of X_i from i = 1 to N.

there are alot of possible combos for the actual groups, there's no one formula to get all the x_i's as you've seen in this thread.

my suggestion to you though would be to look at different combos of different configurations of groups and forget about the ones that don't have N be a multiple of 4.

i'll break it down for you since i'm such a darl

N = number of groups
S = total number of things
X_i = number of objects in group i where i is a whole number from 1 to N and
S = Sum X_i i = 1 to N
N % 4 = 0
X(a) = 2 if a = 0 or X(a) = 3 if a = 1 and a can only equal 0 or 1

wub wrote: